互换性与测量技术基础第三版习题答案VIP免费

1 《互换性与测量技术基础》习题参考解答（第3 版） 第二章 光滑圆柱体结合的公差与配合 1. 孔或轴 最大极限尺寸 最小极限尺寸 上偏差 下偏差 公差 尺寸标注 孔: Φ10 9.985 9.970 -0.015 -0.030 0.015 Φ10015.0030.0 孔: Φ18 18.017 18 +0.017 0 0.017 Φ18017.00 孔: Φ30 30.012 29.991 +0.012 -0.009 0.021 Φ30012.0009.0 轴: Φ40 39.95 39.888 -0.050 -0.112 0.062 Φ40050.0112.0 轴: Φ60 60.041 60.011 +0.041 +0.011 0.030 Φ60041.0011.0 轴: Φ85 85 84.978 0 -0.022 0.022 Φ85 0022.0 2. 1) Xmax = 0.033- (-0.098) = 0.131mm Xmin = 0 - (-0.065) = 0.065mm Tf = | 0.131-0.065 | = 0.066mm 2) Ymax = 0 – 0.060 = -0.060mm Ymin = 0.030 – 0.041 = -0.011mm Tf = | -0.060+0.011 | = 0.049mm 3) Xmax = 0.007- (-0.016) =0.023mm Ymax = -0.018 – 0 = -0.018mm Tf = | 0.023 – (-0.018)| = 0.041mm 4) Xmax = 0.039 - 0.002 = 0.037mm Ymax = 0 – 0.027 = -0.027mm Tf =|0.037 – (-0.027)| = 0.064mm 5) Xmax = 0.074 – (-0.140) = 0.214mm Xmin = 0 - (-0.030) = +0.030mm Tf =| 0.214 – 0.030 | = 0.184mm 6) Xmax =0.009 – (-0.019) = 0.028mm Ymax = -0.021 – 0 = -0.021mm Tf =| 0.028 – (-0.021) | = 0.049mm 3. (1) Φ50)(7f)(8H025.0050.0039.00 Xmax = 0.089mm Xmin = 0.025mm 基孔制、间隙配合 （2）Φ80)(10h)(10G0120.0130.0010.0 Xmax = 0.250mm Xmin = 0.010mm 基轴制、间隙配合 （3）Φ30)(6h)(7K0013.0006.0015.0 Xmax = 0.019mm Ymax = -0.015mm 基轴制、过渡配合 （4）Φ140)(8r)(8H126.0063.0063.00 Ymax = -0.126mm Ymin = 0mm 基孔制、过盈配合 第2 题 2 （5）Φ180)(6u)(7H235.0210.0040.00 Xmax = -0.235mm Ymin = -0.170mm 基孔制、过盈配合 （6）Φ18)(5h)(6M0008.0004.0015.0 Xmax = 0.004mm Ymax = -0.015mm 基轴制、过渡配合 （7）Φ50)(6js)(7H008.0008.0025.00 Xmax = 0.033mm Ymax = -0.008mm 基孔制、过渡配合 （8）Φ100)(6k)(7H025.0003.00...