电路与电子学基础参考答案—科学出版社

第一章习题答案： 1、I=3A,U=4V 2、U=2V 3、(a)耗能=120W 释放能量=120W，(b) 耗能=122W 释放能量=122W 4、I=2.8A U=10V 5、I=0.5A U=9.6V 6、U=-45V 7、U=-4V U=8V 8、I=18A P=1012.5W 9、(a)55S3SB543A33S11SB3A321RUIU)R1R1R1(UR1IRUUR1U)R1R1R1((b) V6UUU2IU51I13U)141(U41U2U41U)4121(BCCBABA 10、3S33SC543B3A433S3SC3B32A21S11SC4B2A421IRUU)R1R1R1(UR1UR1RUIUR1U)R1R1(UR1IRUUR1UR1U)R1R1R1( 11、U=1.2V 12、A12548I  13、I=7A U=14V 14、U=－1/9 V I=17/7 A 15、I=19A 16、(a)UOC=8V Req=16Ω (b) UOC=26/7 V Req=10/7Ω 17、(a)UOC=15V Req=12.5Ω (b) UOC=－4.8 V Req=－0.6Ω 18、U=－40V 19、I=0.5A 20、(a)RL=Req=6Ω PLmax=37.5W (a)RL=Req=9Ω PLmax= 4/9W 21、Req= 400Ω I=0.04A U=4V P=0.16W PLmax= 0.25W 22、UOC=1.25V Req=1.25Ω 第二章习题答案 2-1 （a）u1c (0  )=100V iL (0  )=0A u2c (0  )=0V i2 (0  )=0A (b) iL (0  )=6A uc(0  )=0V ic(0  )=6A u1R (0  )=96V uL (0  )=–12V 2-2 (a) uc(0  )=3V iL (0  )=1.5A ic(0  )=–3A uL (0  )=0V (b) uc (0  )=22V ic (0  )=–1A 2-3 (a) u (t)=6e3t V i (t)= 2e3t A (b) u (t)=4 e t2 V i (t)= 4×105 e t2 A 2-4 (a) i (t)= 2 e t8 A u (t)= 16 e t8 V (b) i (t)= 0.1 e t10 A u (t)= e t10 V 2-5 (a) u (t)=8(1– e t250) V i (t)= 103 e t250 A (b) u (t)=15(1– e t50) V i (t)= 15×104 (1– e t50) A 2-6 (a) i (t)= 3 (1–e 2t) A u (t)= 12 + 3e 2t V (b) i (t)= 2 (1– e t10) A u (t)= 50 + 10e t10 V 2-7 uc (t)=10 + 5 e 5103t V ic (t)= –6 e 5103t A 2-8 uc (t)= –10 (1–e 3t ) V ic (t)= 3–35 e 3t A 2-9 i (t)= 0.0275–0.003 e t410 A 2-10 i (t)= –38 + 38 e t7 A u (t)= –3112 + 3112 e t7 V 改为： i (t)= 4e t7 A u (t)= 56 e t7 V 2-11 2-1...