parameter参数传递的16位乘法器

parameter 参数传递的 16 位乘法器选用课后习题设计题目：设计一个 4 位乘法器，为此首先设计一个 4 位加法器，用例化语句调用这个加法器，用移位相加的方式完成乘法。并以此为基础，使用 parameter 参数传递的功能，设计一个 16 位乘法器。加法器采纳行波进位的方法。4 位加法器设计如下：module ripple_carry_adder(x, y, cin, sum, cout); parameter N = 4; input cin; input [N-1:0] x, y; output [N-1:0] sum; output cout; reg cout; reg [N-1:0] sum; reg q[N:0]; always (x or y or cin)begin:ADDER integer i; q[0] = cin; for(i=0; i<=N-1; i=i+1)begin q[i+1] = (x[i]&y[i]) | (x[i]&q[i]) | (y[i]&q[i]); sum[i] = x[i] ^ y[i] ^ q[i]; end cout = q[N]; endendmodule以此为基础的 4 位乘法器如下：module top(load, rst, clk, dataa, datab, sum); parameter n = 4; input load; input rst; input clk; input [n-1:0] dataa; input [n-1:0] datab; output [2*n-1:0] sum; parameter [1:0] state_s1 = 0, state_s2 = 1; reg [1:0] next_state; reg [2*n-1:0] dataa_register; reg [n-1:0] datab_register; reg [2*n-1:0] sum_tmp,sum_tmp2; wire cout; assign sum = sum_tmp; always (negedge rst or posedge clk) begin: integer i; if (rst == 1'b0) begin for (i = 0; i <= 2 * n - 1; i = i + 1) begin dataa_register[i] <= 1'b0; sum_tmp[i] <= 1'b0; end for (i = 0; i <= n - 1; i = i + 1) datab_register[i] <= 1'b0; next_state <= state_s1; end else case (next_state) state_s1 : if (load == 1'b1) begin dataa_register[n - 1:0] <= dataa; datab_register <= datab; for (i = 0; i <= 2 * n - 1; i = i + 1) sum_tmp[i] <= 1'b0; next_state <= state_s2; end state_s2 : begin if (datab_register[0] == 1'b1) // sum_tmp <= sum_tmp + dataa_register;sum_tmp<={(n-1)'b0,cout,sum_tmp2[n-1:0]}; if (datab_register == 4'h0) next_state <= state_s1; else begin datab_register[n - 2:0] <= datab_register[n - 1:1]; datab_register[n -...