磁化率的测定数据处理一、原始数据记录室温：压强：磁外空管平均值磁内空管平均值磁外样品平均值磁内样品平均值△m空管△m样品▽m样品-▽m空管m/g莫尔氏盐18.321018.3210518.318918.3189025.792425.7924525.954525.95455-0.002150.162100.164257.47140h=11.2cm18.321118.318925.792525.9546硫酸亚铁19.866519.8665019.864519.8665025.954925.9549026.154626.15460-0.002000.199700.201706.08840h=10.6cm19.866519.864525.954926.1546铁氰化钾17.728017.7280017.725217.7252024.315224.3151524.349324.34930-0.002800.034150.036956.58715h=10.9cm17.728017.725224.315124.3493亚铁氰化钾18.811718.8117018.808918.8089025.180026.1800525.172526.17520-0.00280-0.00485-0.002057.368351h=11.1cm18.811718.808925.180125.17522二、计算莫尔氏盐磁化率，求出磁感应强度；再由标准样品求出其余样品磁化率1、计算莫尔氏盐磁化率T=26.5℃=299.65KM莫氏盐=392.14=3.9707×10-7m3/kg=1.5571×10-7m3/mol相应的磁场强度H==√2×0.16425×9.8×392.144π×10−7×7.47140×1.5571×10−7=2.9386T2、由标准样品求出其余样品磁化率相关数据如下：样品（Δm莫氏盐−Δm空）/gH/cmm/g莫尔氏盐392.140.1642511.27.47140硫酸亚铁278.030.1997010.66.08840铁氰化钾329.250.0341510.96.58715亚铁氰化钾422.39-0.0048511.17.36835样品摩尔磁化率可由以下公式求的：χ样品=(Δm样品−Δmm空)(Δm校准剂−Δm空)×m校准剂m样品×M样品M校准剂×h样品h校准剂χ校准剂则有：χ硫酸亚铁=(Δm硫酸亚铁−Δmm空)(Δm莫氏盐−Δm空)×m莫氏盐m硫酸亚铁×M硫酸亚铁M莫氏盐×h硫酸亚铁h莫氏盐χ莫氏盐¿0.199700.16425×7.471406.08840×278.03392.14×10.611.2×1.5571×10−7m3/mol¿1.5589×10−7m3/mol3同理有：χ铁氰化钾=0.034150.16425×7.471406.58715×329.25392.14×10.911.2×1.5571×10−7m3/mol¿0.3001×10−7m3/molχ亚铁氰化钾=−0.004850.16425×7.471407.36835×422.39392.14×11.111.2×1.5571×10−7m3mol¿−0.04977×10−7m3/mol3、根据χm计算样品的未成对电子数a、硫酸亚铁由χm=NAμm23KT×4π×10−7得：μm=√3χmKTNA×4π×10−7¿√3×1.5589×10−7×1.380662×10−23×299.656.02×1023×4π×10−7J2/T2=5.0573×10−23J2/T2b、铁氰化钾μm=√3χmKTNA×4π×10−7¿√3×0.3001×10−7×1.380662×10−23×299.656.02×1023×4π×10−7J2/T2=2.2189×10−23J2/T2又因为、μB=9.274078×10-24，所以：当n=1时，μm=1.6063×10-23J2/T2；当n=2时，μm=2.6231×10-23J2/T2；当n=3时，μm=3.5918×10-23J2/T2；当n=4时，μm=4.5434×10-23J2/T2；当n=5时，μm=5.4866×10-23J2/T2。由此可以看出:当n=4时，μm=4.5434×10-23J2/T2，接近μm=5.0573×10−23J2/T2，则硫酸亚铁的未成对电子数是4。当n=2时，μm=2.6231×10-23J2/T2，接近μm=4.5434×10−23J2/T2，则铁氰化钾的未成对电子数是2。4因为χ亚铁氰化钾=−0.04977×10−7m3/mol，故亚铁氰化钾是反磁性物质，未成对电子数为0。5
