高一数学答案 第 1 页 共 4 页 2016～2017 学年度第二学期期末质量检测 高一数学参考答案及评分标准 2017.7 一、 选择题：本大题共 12 小题，每小题 5 分，共 60 分. BCBD BCDA DCAB 二、填空题：本大题共 5 小题，每小题 5 分，共 25 分． 13． 15 14．1 15． 43 310− 16．π 5π[,]33− 17． 6 三、解答题：本大题共 5 小题，共 65 分． 18．（1）设日销售量为 x ，则31(049)3010Px==��，31(50100).3010Px<==� 由互斥事件的概率加法公式， 111(0100)(049)(50100)10105PxPxPx<=+<=+=����． ·························· 6 分 注：直接按照古典概型的计算公式，得331(0100).305Px+<==�同样给分. （2）日销售量低于100 枝共有6 天，从中任选两天促销共有15n =种情况；日销售量低于50 枝共有 3 天，从中任选两天促销共有3=m种情况．··········································· 10 分 由古典概型的概率计算公式，所求概率31155P ==．······································ 12 分 19.解：（1）因为1ω =rad / s ，所以t s 后，点 P 在角 π2t+ 的终边上. 由三角函数的定义可知πsin()2yt=+cost=. 即( )cosf tt=，[0,)t ∈+∞ .················································································ 4 分 （2）由（1）可知，3cos5A =，12cos13B = −.··························································· 6 分 因为,(0,π)A B∈，所以4sin5A =，5sin13B =. ··············································· 8 分 所以( )coscos[π()]f CCAB==−+ cos()AB= −+ (coscossinsin)ABAB= −−·············································· 10 分 31245[()]513513= −× −−× 5665=. ·····································································...
