Hibernate如何映射enum(枚举)

Hibernate 如何映射enum（JDK5.0 中的枚举类）方法一 先看一张表： Create table test( Test_id integer not null auto_increment, gender Enum(MALE, FEMALE) ) 在 hibernate 的pojo 中可以这样描述： public final class TestVO { private Integer id; public static enum Gender { MALE, FEMALE; } private Gender gender; public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } public Gender getGender() { return gender; } public void setGender(Gender gender) { this.gender = gender; } } 而后要自己写一个适合 enum 的在 hibernate 中的类型，虽然 hibernate 已经有了 Org.hibernate.type.EnumType. 但是这个类是用于 annotation 的（在后面会讨论怎么用annotation 技术映射 enum）. 创建一个自己的 EnumUserType: import java.io.Serializable; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.sql.Types; import org.hibernate.HibernateException; import org.hibernate.usertype.UserType; import org.apache.log4j.*; public class EnumUserType> implements UserType { private Logger log = Logger.getLogger(EnumUserType.class); private Class clazz = null; private static final int[] SQL_TYPES = { Types.VARCHAR }; protected EnumUserType(Class c) { this.clazz = c; } public int[] sqlTypes() { return SQL_TYPES; } public Class returnedClass() { return clazz; } public Object assemble(Serializable cached, Object owner) throws HibernateException { // TODO Auto-generated method stub return cached; } public Object deepCopy(Object value) throws HibernateException { // TODO Auto-generated method stub return value; } public Serializable disassemble(Object value) throws HibernateException { // TODO Auto-generated method stub return (Serializable) value; } public boolean equals(Object x, Object y) throws HibernateException...