1ILDDDDDDBDDDDDBDDDDDDDDDDDDDADDFDDDDDDDDDDDDDDDDD磁场测试题1DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD[]ADDDBDDDCDDDDDDD2DDDDDDDDBDDDDDDDDDDDDDDDDDDDDDDDDDDDDDADDDDDDDDDDDBDDDDDDDDDDDDDDDBDDDDDDDDDDDBDDDDDDDDDDDDDDDDDDDDDDDDCDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD3DDDDmDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD[]4DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDFDDDDDDDDDDDDD[]2ADF>FDADDDDDDD12BDF>FDADDDDDDD12CFFDDDDDDDDDDDD2DDDDDDDDDDDDD5DACDDDDDDDDDDDDDDDDDDDDDDDDDDR-mVDR-百DDDDDDDm~r=Bq-2gh6DAR-mVDR-而皿F'DDDDDDDD2gh二v2DEq=mgDDDACODDqODDmvDBDRDDq_2兀m~~BTDDDqODDmBDTDDADDD7DADDDDDDDADBDDDDDDDDDB粒子OD3DDDDDDDDDDE89_2兀=—3-DDDDDDDDDDDDDDDDDDD兀mA-3BqABADDODDDDDDDDDvBqUADDDD8DBCBqADDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDrDDDDDDDDq甲〉食0DDDDDDDDDDDDDDDDDDDDDDDD9DAC10DDBDDvB-BBqBv甲^=Bq甲2兀mBBqB2兀mB3BqBBDDDDDDDDDDDmvq—AABqmvABB、洛□ADDDmv乙乙乙Bq乙,(m+m)v'r=甲乙叮B(q甲-q乙)mv一mv=(m甲甲乙乙甲r=rDDCDDDDDDDDDDDDDDDDDDDDDDDDDDDD(qBR)2DDDDDDDDDDDDDDDDDDDDDDDDD2mDDDDDDDqDDDmDDDDDDDDDDDDDDDDDDDmvr=DDDDDBq皿训BarDDDDqDDDDmADDDDDDDDDDDDDDDDDDDDDDEv=DDDDDDDDDDDDDDDDDDDDDDDDBmvDr=而DmqD'qmDDDDDDDDD12DDDDDDDDDDDDDDDBqv=EqODDDDDDABDDDDDDDDDDDDDDDDDDDDDDD〃甲＞役ADDDDDq甲ADDDDDDDD=EdDDDDDDDD乙)VD乙Uq1=—mv22DDDDQADDDDDDDDDDDDCDDDDDFOODrDDDDBDDDDDDDDDDDrDDDDDDDDDdP—D(dDDDDDDDDsF=4各叮Eq=BqvDDADBDDDDDBda10DDDDDDDSBdvP=可（一R）DDDDDdIi3nnnnndnnbnnnnnnnnnnnnnaDDDDDDDDDDab=ad=acm|B|=|B=|BIDDDDDDDDdc|baDDDDDDDDbDDdai4nnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnnDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD15（d,斗d）16D7DDDDDDDDDDDDDDDDDDabDDDDDDDDDDDDDmgsin0=Fcos0=BILcos040.02x10x-=竺tan0=3BL1.0x0.2=3ADDDDDDDDDDER=—（R+r）=70I0N17DDDDDOC=rDDOD=2rDD1DDDDDDDDDDDDDDBqv0v2=m-ogrmvr=游°2兀m1=DDDDDDDDDDDDDBq兀m2BqDDDDDDDDDDDD2xmVoBq2m=百ADDs兀、mB+fE=（2+戸Bq2Bq—Eqa2Dr=2tEE=与a2mE23DCDDDDDDDDDEqr=E——mv2EKD20KD=mv2018DDDDD1DDDDDDDDDDDDDDDDDF=Eqmgsin0+Fcos0—f=maDF+Fsin0一mgcos0=01DDDDDF=1mg2S=—at22DDDDDDDDDDg（2-卩）t2D2DDDADDDDDBqv=mgcos0-Eqsin0mg2Bq°DDDDDDDD11D3DDDDDDDDDDDmg(L+S)sin9+Eq(L+S)cos0-W1=_mv22W=mgm3g28B2q219DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDv0D2ODDmv2兀mr=onT=—BqBql=r(1+cos45。)=OCCDxDDDDDDDDDDDDDDDDDDDDDDl=辺rlOD2mvDDDDDD5兀mDDDDDDDDDDDEq—V=V—tn00m2Eq0ODDDDDDDDDDD兀m2BqADDDDDD7Km2mvt=t+t+t=+01234BqEq
