1/3物理部分参考答案（年市三检）第Ⅰ部分（选择题）．．．．．．．．第Ⅱ卷（非选择题）．（分）（）（分）；（）（分）；（）（分）．（分）（）（分）（）如图所示（分）（）（分）（）（分）．（分）解：（）设列车正常车速为，减速后车速为，减速和加速过程位移为，时间均为，减速后匀速行驶位移为，时间为，由运动学公式可得：222112vvas················································································（）分222tvs·························································································（）分212sss·····················································································（）分解得：ms12800···········································································（）分（）设列车正常车速通过位移所用时间为′，则有：avvt211······················································································（）分1vst····························································································（）分tttt212···············································································（）分解得：st280··············································································（）分．（分）解：（）由题意可得粒子在匀强电场中做类平抛运动，设粒子在匀强电场中运动时间为1t，加速度为a，粒子经过点的速度与轴正方向夹角为θ，由牛顿第二定律和运动学公式可得：2/3maEq····························································································（）分102tvL····························································································（）分21213atL·······················································································（）分1atvy······························································································（）分220yvvv····················································································（）分0tanvvy·····························（）分解得：qLmvE2320················（）分02vv·································（）分060·································（）分（）由题意可知粒子在匀强磁场中做匀速圆周运动，设粒子在匀强磁场中做匀速圆周运动的半径为R，可得：RmvqvB2···············...
