等差数列练习题(一)1
已知为等差数列,,则等于A
7【解析】∵135105aaa即33105a∴335a同理可得433a∴公差432daa∴204(204)1aad
【答案】B2
设nS是等差数列na的前n项和,已知23a,611a,则7S等于()A.13B.35C.49D.63故选C
等差数列{}na的前n项和为nS,且3S=6,1a=4,则公差d等于A.1B53C
-2D3【答案】:C[解析]∵31336()2Saa且3112=4d=2aada
已知na为等差数列,且7a-24a=-1,3a=0,则公差d=A
2【解析】a7-2a4=a3+4d-2(a3+d)=2d=-1d=-12【答案】B5
若等差数列{}na的前5项和525S,且23a,则7a()A
15答案B6
在等差数列na中,284aa,则其前9项的和S9等于()A.18B27C36D9答案A7
已知{}na是等差数列,124aa,7828aa,则该数列前10项和10S等于()A.64B.100C.110D.120答案B8
记等差数列{}na的前n项和为nS,若112a,420S,则6S()A.16B.24C.36D.48答案D9
等差数列na的前n项和为xS若=则432,3,1Saa()A.12B.10C.8D.6答案B10
设等差数列{}na的前n项和为nS,若39S,636S,则789aaa()A.63B.45C.36D.27答案B11
已知等差数列}{na中,12497,1,16aaaa则的值是()A.15B.30C.31D.64答案A12
已知等差数列na的前n项和为nS,若1221S,则2581