因式分解练习专题练习+全国中考因式分解1
利用乘法公式,展开下列各式:(1)(9x–5)2=__________________
(2)(2x+7)(7–2x)=__________________
化简–2(x2+3x–5)+4x2–7x+5=__________________
(2)展开(–2x+3)(4x–5)=______
B为两多項式,已知A=x2+4x–3,且A+B=2x2+4x–2,求B=______
已知x+3=0,则x2+4x+3=__________________
化简下列各式:(1)(4x2+3x+5)+(2x2+5x–3)=__________________
(2)(–4x2+x–3)–(–6x2–2x–4)=__________________
因式分解(a2–2a+1)–b(a–1)=__________________
因式分解6(a2–b2)–(a+b)=__________________
(x2–3x+5)–(ax2+bx+c)=3x2–4x+5,則a+b+c=______
在下面空格中填入适当的式子
(1)(–7x2–8x+6)+(______)=0
(2)(______)+(4x2–7x+4)=–x2+8x–3
设xy–x+y=5,求(x+1)(y–1)之值=______
若(x2+)–=0,则A=______
若x=,则(x–2)(x+2)之值为______
若一元二次式B=–x+3x2+5,则(1)x2项系数为______
(2)x项系数为______
(3)常数项为______
展开下列各式:(1)(–1–2x)(–1+2x)=____________
(2)(2x–1)(–3x+5)=________________________
(3)(–5–6x)2=_