气固相催化动力学例题VIP免费

第五章气固相催化动力学例题1. 用图示讨论固体催化剂催化下的气相反应A(g) → R(g) 整个反应过程？可能存在几步阻力和控速步骤？写出各步速度方程？（20 分）解：三步阻力：气膜，孔隙，表面应力。控速步骤：气膜，表面应力， （吸附，反应，脱附）-rA = k g(CAg - CAS) = ksCASn = η kCAnAgCAsCgk2. Giving the gaseous reactant A through a gas film a rate equation Answer : -rA = kg (CAg-CAS ) 3. Try to give the reaction on the surface of a solid according to a irreversible first order rate answer : -rA = k CAS = η kCAη —催化剂有效因数，CA –孔内催化剂平均浓度。4. Explaining the Thiele modulus. answer : Φ s = L evDkL---- 催化剂特征长度，kv----一级反应以催化剂孔体积为基准的速度常数。De----孔内反应物的有效扩散系数。Φ s----高代表催化剂的孔隙阻力大。5. What seeps are the reaction processes of a solid catalyzed reaction included. Answer: 1)反应物过气膜到催化剂表面扩散2）反应物过孔隙到催化剂孔内扩散3）反应物在内孔表面上的反应（内表面过程）4）产物过孔隙反向扩散到外表面5）产物过气膜反向扩散到气流主体。1、 用图示讨论固体催化剂催化下的气相反应A(g) → R(g) 整个反应过程？可能存在几步阻力和控速步骤？写出各步速度方程？（ 20 分）解：三步阻力：气膜，孔隙，表面应力。控速步骤：气膜，表面应力， （吸附，反应，脱附）-rA = k g(CAg - CAS) = ksCASn = η kCAnAgCAsCgk2、 Giving the gaseous reactant A through a gas film a rate equation Answer : -rA = kg (CAg-CAS ) 3. Try to give the reaction on the surface of a solid according to a irreversible first order rate answer : -rA = k CAS = η kCAη —催化剂有效因数，CA –孔内催化剂平均浓度。6. Explaining the Thiele modulus. answer : Φ s = L evDkL---- 催化剂特征长度，kv----一级反应以催化剂孔体积为基准的速度常数。De----孔内反应物的有效扩散系数。Φ s----高代表催化剂的孔隙阻力大。7. What seeps are the reaction processes of a solid catalyzed reaction included. Answer: 1)反应物过气膜到...