1 . 1.受弯构件: 1. 1 基本资料 1. 1. 1 工程名称:工程一 1. 1. 2 混凝土强度等级:C30 fc = 14.33N/mm ft = 1.43N/mm 1. 1. 3 钢筋强度设计值 fy = 360N/mm Es = 200000N/mm 1. 1. 4 由弯矩设计值 M 求配筋面积 As,弯矩 M = 120kN· m 1. 1. 5 截面尺寸 b× h = 250*500mm ho = h - as = 500-40 = 460mm 1. 2 计算结果: 1. 2. 1 相对界限受压区高度 ξb ξb = β1 / [1 + fy / (Es * εcu)] = 0.8/[1+360/(200000*0.0033)] = 0.518 1. 2. 2 受压区高度 x = ho - [ho ^ 2 - 2 * M / (α1 * fc * b)] ^ 0.5 = 460-[460^2-2*120000000/(1*14.33*250)]^0.5 = 80mm 1. 2. 3 相对受压区高度 ξ = x / ho = 80/460 = 0.173 ≤ ξb = 0.518 1. 2. 4 纵向受拉钢筋 As = α1 * fc * b * x / fy = 1*14.33*250*80/360 = 793mm 1. 2. 5 配筋率 ρ = As / (b * ho) = 793/(250*460) = 0.69% 最小配筋率 ρmin = Max{0.20%, 0.45ft/fy} = Max{0.20%, 0.18%} = 0.20% 2.受剪构件: ( 1 )构造配筋 1. 1 基本资料 1. 1. 1 工程名称:工程一 1. 1. 2 混凝土强度等级:C30 fc = 14.33N/mm ft = 1.43N/mm 1. 1. 3 箍筋抗拉强度设计值 fyv = 210N/mm 箍筋间距 s = 200mm 1. 1. 4 由剪力设计值 V 求箍筋面积 Asv,剪力设计值 V = 100kN 1. 1. 5 截面尺寸 b× h = 250× 500mm ho = h - as = 500-40 = 460mm 1. 2 计算结果 1. 2. 1 0.7 * ft * b * ho = 0.7*1.43*250*460 = 115348N ≥ V = 100000N 1. 2. 2 当 V ≤ 0.7 * ft * b * ho、 300 < H ≤ 500mm 构造要求: 箍筋最小直径 Dmin = 6mm,箍筋最大间距 Smax = 300mm Dmin、 Smax 的配箍面积 Asv# = Dmin ^ 2 * π / 4 * S / Smax = 19mm 最小配箍面积 Asv,min = 19mm ( 2 )计算配筋 1. 1 基本资料 1. 1. 1 工程名称:工程一 1. 1. 2 混凝土强度等级:C30 fc = 14.33N/mm ft = 1.43N/mm 1. 1. 3 箍筋抗拉强度设计值 fyv = 210N/m...