材料物理导论(熊兆贤着)课后习题答案第三章习题参考解答

《材料物理导论》 习题解答 第三章 材料的电学 EC 0.29eV 0.05eV ED EF Ei EV 311231915/)(/1006.4)3001038.1106.122.0exp(21110211)(22.005.029.0212.1)(,12.1.1cmeNEfNneVEEEEEEEEEEEEeVESikTEEDDDDFDiFDicFDDcDgFD的查解：。少子；多子解：)(/1013.1)(/105.1.239203150cmNnpcmNnNnDiDDieV22.0J1053.3EEcm/102Ncm/100.1NNNlnkTEEPcm/1045.8102)103.1(pnncm/102109101.1NNpTNP,NN.320VF315A319VAVVF34152102i3151516DAAD代入可得取，取型半导体，有对于杂质几乎完全电离在室温，较少且又型半导体补偿后解：时可保持强电离。则有令，仅考虑杂质电离有低温区，忽略本征激发解：318D318DDD2/1kT/ECDDD0cm/1032.1Ncm/1032.1NN9.0n)eNN8(1N2nn.4DEg=1.12eV 《材料物理导论》 习题解答 KTmkNDTTkEkTmNDNDnTkENNDTkENNNnNNTkEETkEENnTkEETkEENndnDDdncDDDcDDcDDDcDcFFDDDFDFDDD125)2()_ln(ln)2/3()1)(/)2(2_,_)/exp()(2_),/exp()(2ln)exp(21)exp(,)exp(211.532/3002/3000000（代入将总数的百分比为未电离的施主杂质占令代入上式杂质饱和电离时当解： 31319pniipniiicm/1029.2)19003900(106.1471)(q1n)(qn1.6解：661119163163221161910310108.21085.3/8.108.101350106.1105/105,/1051085.3)5001350(106.1103.1)(/103.1300.7innDnDipniiicmqncmncmNSicmqncmnSiK则的密度本征又的时解：cm34.1400106.11017.11pq1cm/1017.1)33.2500/(1002.68.10105.4Np.81916p316235A解：《材料物理导论》 习题解答 mEsqmmqnnndsnnnnnn18174417194311048.11048.110101.01048.1106.110101.926.01.0.9解：3.16.01781.0SlRcm781.08000106.1101nq11.101915n解：225112251123312319193103.421023.412.4400)2(5.361065.3365.3)1010/(101.926.0...