数列复习 ( 第 2 课时 )【问题导学】1S1nnSS 111nn1nn 【预习自测】C12n5699【例题探究】(1)2n n 12n 11,12,2nnn1n3,12 ,2nn n231231231231n-11 3 2 5 27 2(21) 221 2 3 25 2(23) 2(21) 2-1 2 22 22 22 2(21) 2=22222+1 (21) 22-=21 (21) 21-23 (23) 2nnnnnnnnnnnnnnnnnnnSn 解:由题意知:S故 S上述两式作差得S()(12 )111246239273124222392733222222339273321-233=131- 3323223nnnnnnnnnnnnnnnnnnS解:由题意知:S故S上述两式作差得S(1)【课后作业】21n 2 1n 61311(1)(1)23nn n 222nn122nn 21122221nnna 提示: