热学(秦允豪编)习题解答第二章分子动理学理论的平衡态理论VIP免费

03121131211332332aaaaaa普通物理学教程《热学》（秦允豪编） 习题解答 第二章 分子动理学理论的平衡态理论 2.2.1 解：（a）归一化 aaaAAdxdxxf12，aA21 或：可直接由面积求。 12AadxxfS，aA21   04122aaxadxaxdxxxfx      0000aaaadxxxfdxxxfdxxxfdxxfxdxxfxx aaaaaaaaxxaxdxaxdxa022020202212122212121  232226121axadxxadxxfxxaa （b） aaaAaAdxdxxf20212，aA21（或 12  aA）   azaaadxxxfx2222121   aaaaaadxxfxx20233223486123121 （c） 1212Aadxxf，aA1 确定  xf的关系，由121211xxyyxxyy，得  02aaaxxf  aaxaxf02  aaaadxxaxadxxaxadxxxfx02022211 aaxaxaxaxa032203223121131211  aadxxaxadxxaxadxxfxx032023222211 aaxaxaxaxa04320432413114131124444261413141311aaaaaa （d） 1221aAdxxf,aA1 依题意得解析式 axaAxf0   aaaxaAxf22  aaaaxdxaxaAdxxaAdxxxfx022202 aaaaaxAxaAxaA2223032233 22333241831aaaaaaaaaa32  aaaaaadxxAdxxaAdxxaAdxxfxx20022233222 aaaaaxaxaxa23242042324141 3344242832164141aaaaaaaa 22226731441541aaaa 2.2.2  242xAexfx，将 xf归一化，求A。 解： 0232141442AdxxAedxxfx 32323A    xxfdxxfP 0002.064464exp4232232xxex 2.3.1 解： dvvekTmNdvvNfdNvkTm2223224 （引入svvu ， svdvdu ） dvvekTmNvkTm23232323234 duuAeduvvevAusus2232233221...