2024年新加坡入学考试英语数学VIP免费

Nａmｅ:__＿____＿_______＿_＿___＿＿__＿__＿＿__＿＿_Identityｎo:_____＿＿＿__＿＿____＿__＿_____Ｄate:___＿_____＿_＿____＿_SeatNo：＿＿_______ＢCAACAＤEMYＳＣHOOLOFBUILDINＧ＆DＥVEＬOPMENTＳIＮGAPＯＲEＭAＴHEMAＴICＳSCREＥＮINＧＴＥSＴSetA1.5HOURSInstrucｔiｏnstocandidａtes1.Doｎotturnovｅrthispaｇeunｔilyoｕaｒetoldtodoso．2.Chｅckthatyｏuhavethecorrecteｘamｐａｐer，ｎuｍberｏfｐaｇｅsanｄｑｕｅstioｎs.3.ThiｓpapercoｎsisｔsofTEN(1０)questiｏns(1０0maｒks).AnswｅrALLquｅstions4.WrｉteyｏurＮaｍe,ＩCNO.andＳeatＮo.onthiscｏvｅrpage．5.AｌlanswｅｒsareｔobeｗritteｎinTＨISbｏoklet.6.DｏNOＴteａrouｔanyｐａｇe.ThｉsbooｋｌｅtistｈeprｏperｔyｏｆBCAAcademyandmustnotbereｍovｅｄfｒｏmｔheｔeｓtcentre.7.Ｍobiｌｅphoｎesaｒetoｂｅｓｗitcｈedｏｆfａnｄeｌectｒoｎiceqｕiｐmenｔsａｒeｎotallｏwｅdtobeused．8.Candidａｔｅsaretｏbringtheirownnon－proｇｒammablｅｓciｅｎtiｆicｃaｌcuｌator.Unlessotheｒｗiｓestａｔed,leａveyourａnswｅrsin3ｓｉｇｎificaｎtｆigｕｒes.Ｕnｌessthequｅstｉonsrｅquiretheａnswersinterｍofπ,thecａｌcｕlａtorvalueｆorπ=3.142shouldbeusｅｄ.Ifworkiｎｇisｎeededforanyquｅｓｔioｎ,itmustbesｈoｗｎwiｔhｔheanswer.Oｍisｓｉonoｆesｓenｔiａｌwｏrkingwillｒeｓultiｎlossofｍarks．1.Siｍｐliｆyｔｈefolloｗingexpreｓｓioｎｓusｉnｇfracｔioｎsｏｎly.Shｏｗyｏuｒｗorkiｎｇｃleａrly.(a)(−1517)0¿(34)1(5marks)(b)ﻩ(0.16)12¿)2.96１）−12(5mａrks)(ａ)(−1517)0¿(34)1=34(b)(0.16)12¿(1２．96）−12=19FｏrOfficialUsｅ:ＴｅstCｅｎtｒe：TestDａtｅ:Maｒｋｓ(/1０0):Maｒker：Checker:ﻩﻩﻩﻩﻩﻩﻬ2.(a)ﻩＧivenif27x+y=81and３x−y＝2７,finｄ9x2−y2.(5markｓ）(b)ﻩ(2.1x1032z)2−3(6.5x103z−1)=2.46x10−5,fｉndz.(5mａｒｋs）(a)9x2−y2＝656１(b)z=53ﻬ3.(ａ）Ｔｈefollowｉngfigｕｒesｈowsaright-ａnglｅdｔrianglｅanｄiｔsdｉmensioｎs．Findx.（4maｒｋs)(x+3)2+(2x−1)2=(3x−2)2X＝7±√734ﻩ(x+3)cm(2x-1)cm(3x-2)cmﻬ3.（b)Apencilcａseｃｏntains2grｅen，6ｒｅｄand1２orangepens.Apenispickedｏｕtatrandomａnｄreplaｃed．Ａseconｄpenistｈｅnpiｃkedｏuｔaｔｒａnｄｏmanｄnotreplaced.Athirdpｅnisｆinaｌｌｙpｉcｋedｏuｔａtrandom．Fｉｎdｔhｅprｏｂabilｉtｙthaｔａllｔhreepensｐiｃkedareofdifｆeｒentｃolourｓ.（6mａrks)Ｐ＝544754.(a）Tｈｅdiａgrａmsｈowsfourｐｏiｎts,A,B,Ｃ,D,onｌｅｖelgrｏund.ＩｔisgｉｖenthatDiｓｄuｅNorthoｆC,∠ABC＝52°,∠ACＤ=１20°and∠AＣＢ=9０°.ﻩﻩFinｄ:(i)ﻩ∠ＢCＤ,ａｎd(ｉｉ)ＢeａriｎgofBfｒomＡﻩ(5mａrks)ﻩﻩ(i)∠BCD＝15０ﻩ(ii)eaｓtbyｎｏrｔｈ１8ﻬCNorthDAB1205221m62m66°23°RQ4(b)ＧｉvｅｎｔhatAD＝BE=1２ｍ.∠BEC=５５°aｎｄ∠ADＣ＝68°.FindlｅnｇthAB.(5mａrks)ﻩﻩﻩﻩAB=12×(sin68°−sin55°)ﻬ5.Iｎthediａｇram,PSTiｓasｔraiｇhtline,ＱR=2１ｍａndRS=62m.ＴheangｌeofdepreｓsiｏnofRfroｍQｉs2３．ThｅａngleofdepｒessionｏfTｆｒomRis66.ﻩ(a)HowmuchhigherisQthanR?(b)Calculate∠RST.(c)CalculatethelengthofST.(10marks)68°55°ABDECH＝(21×sin23°)m∠RST=67°L=（62×sin47°sin66°)mﻩﻩﻬ6.OABaｎdORSaretwosｅｃtorsｗiｔhcommoncｅntreＯanｄradiiOＡaｎdＯRrespecｔiveｌｙ.PQRSａrecｔａngleinｗhichＰQ=18cmａndQR=ｒcm.ＲSistangenttotheaｒｃＡＮBａｔＮ,PO=OＱandMＮ=4cm．ﻩﻩﻩ（10marｋs)∠ROS=π－arcsin93609409L=(814×(π-arcsin93609409)+8)mS=812×(π−arcsin93609409)Calculate(a)∠ROSinradians,(b)theperimeteroftheshadedregion,and(c)theshadedarea.Hint:Lengthofarc,S=rθAreaofsector=12r2θwhere,r=radiusθ=angleofthearc(inradian)7.Intheｄｉaｇraｍ,thepointｓＡ，Ｂ，Can...