公式:)2sin()2cos(tan?330sin0作用:把2700~3600角的三角函数转化为锐角的三角函数。sincos)2tan(诱导公式的记忆方法如下:注:符号是将看成锐角时原函数的符号。函数名不变,符号看象限。)2sin()2cos(tansincos)2tan(sin)sin(cos)cos(tan)tan()2sin()2cos(tansincos)2tan(sin(sincos(costan(tan练习1求证:322sin)cot()(csc)cos()2tan()cos()(sin练习2化简:)sin()3sin()cos()cos()2sin(练习3.已知求54)sin()tan(,cos练习4:已知求33)6cos()6(sin)65cos(2练习5若求的值。1)(cos2)cos(33)2cos(3)2(sin3cos2)(223xxxxxxf)3(f)]180(sin[)]180(cos[)3603cos()3604sin(sincoscos(180)[sin(180)]aaaa×=°+×-°+sincos(cos)sinaaaa×=-×解:原式==-1.练习练习66化简化简::)180sin()180cos()1080cos()1440sin(63131053p练习7求值:sin-cos-sin练习8求值:sin(-1200º)·cos1290º+sin(-120º)+cos(-1020º)·sin(-1050º)+tan855º奎屯王新敞新疆)()2cos()2sin(])12([sin2])12([sinZnnnnn)2cos()2sin(]2)sin[(2]2)sin[(nnnnsin()2sin()sincospaapaa++-=sin2sinsincosaaaa--=3cosa=-奎屯王新敞新疆练习9化简:解:原式=练习10求证3tan)360sin()540sin(1)180cos()cos(1223)360tan(1)720tan(1222[cos()sin()cos()12sin()]cos(2)pqpqpqqpqp-++×-+-×--练习11已知,求:的值.