不等式性质不等式性质不等式性质不等式性质两个实数大小的比较两个实数大小的比较ba1ba)2(ba1ba)1(,0b,a则若比商法比商法比差法比差法0baba0baba对称性abba传递性cacb,ba加法单调性cbcaba移项法则bcacba乘法单调性0cbcac0cbcacba同向不等式相加dbcadcba同向正值不等式相乘bdac0dc0ba正值不等式乘方、开方、倒数0bab/1a/1)1n,Nn(bann且)1n,Nn(bann且xy2yx0y,x)2(xy2yx)1(22注意)aaa(aaanaaa0a,,a,an21nn21n21n21”号取“当且仅当则若无理不等式0)x(g0)x(f)x(g)x(f0)x(g0)x(f)x(g)x(f)12或2)x(g)x(f0)x(g0)x(f)x(g)x(f)20)x(g0)x(f0)x(g0)x(f0)x(g)x(f或0)x(g0)x(g)x(f0)x(g)x(f)3等式分式不)x(g)x(faa,1a0)x(g)x(faa,1a)4)x(g)x(f)x(g)x(f时当时当指数不等式1a)x(glog)x(flog)5aa1a0)x(g)x(f0)x(g0)x(f)x(g)x(f0)x(g0)x(f对数不等式复习时当0a)1(axaxaxax22或axaaxax22b/ab/a,baba)2(aaa,aa)3(22aa)4(abba.1基本性质cacb,ba.2cbcaba.3dbcadc,babdac0c,babcac0c,ba.4bdac0dc,0ba)1n,Nn(ba0bann)1n,Nn(ba0ba.5nn如何证明?22.D22.C0.B.A)(,22)1:1的取值范围是则满足,角例B)4()3.(D)4()2(.C)3()1(.B)2()1(.A)(1ab0ba)4(babcac)3(bcacba)2(ba0ba)1(,Rb,a)22222和和和和其中真命题是下面四个命题:D条件的是_________________1b,1a1ab,2ba)3(必要不充分___________________blog,alog,a,1ba0)4(a1bb大小关系是的alogablogbba1bdeace:.0e,0dc,0ba2求证已知例0ba:证明0dc0bdac0ac1bd10e0acebde的大小与比较大小和比较和已知例)x1(log)x1(log,1a,1x0)2(NM,1aaNa1aM,1a)1(4aaqnmp.Dqnpm.Cnqmp.Bnqpm.A)(q,p,n,m,0)nq)(mq(,0)np)(mp(,qp,nm.1的大小顺序是则若练习:A不能确定顺序是的大小则若.D0dc.Cd0c.B0dc.A)(d,c,0ba,bdac.2D0)ba(log.D)21()21.(C1ba.Bb1a1.A)(,ba.32ba一定成立的是则下列不等式中若C既不充分也不必要条件充要条件必要条件充分不必要条件”的“”是那么“若.D.C.B.A)(yxyx0xy,Ry,x.4Aaxax.Daaxx.Caxax.Baaxx.A)(,0ax.522222222成立的是那么下列各式中一定若A___________x1),3,3(x.6范围是的取值那么已知),31()31,(___________b1ba1a,0ba.7的大小关系是与则若b1ba1a333baba0ba.8求证:若)1a(2)a(f)x(f)2(1ax)1(1ax,13xx)x(f.92求证:已知.0)1m2(x)1m2(x,Rx,m.1022的大小与比较设.)3(f,5)2(f1,1)1(f4cax)x(f.112的取值范围求满足已知函数)x(g)x(f)x(g)x(g)x(f)6)x(g)x(f)x(g)x(f)x(g)x(f或