高中数学 第三章 变换的合成与矩阵乘法（一）同步练习 新人教A版选修4-2-新人教A版高二选修4-2数学试题VIP专享VIP免费

第三章变换的合成与矩阵乘法同步练习(一)1、41214211（）A、12631B、12620C、12260D、123612、若cossinsincosA，则nA（）A、nnnncossinsincosB、nnnncossinsincosC、nnnncossinsincosD、nnnncossinsincos3、211401103-121-0201()A、01407B、2-41-2C、42-21-D、42214、与点通过矩阵100211M和100312M的两次变换效果相同的变换是（）A、310021B、61001C、210031D、100615、关于矩阵乘法下列说法中正确的是（）A、不满足交换律，但满足消去律B、不满足交换律和消去律C、满足交换律不满足消去律D、满足交换律和消去律16、已知01311B，存在矩阵__________A，使得BAAB。7、对平面内的点P先作变换1002M，再作变换1-102-N，用一次矩阵_________对应的变换作用在P上，效果与这两次变换的效果是相同的。8、若10611013x，则7.0x8.0x。9、（1）已知32-412001AB,，计算BAAB,；（2）已知5342,,CB10010001A，求CABCACAB,,,。10、已知A=cossinsincos，B=cossinsincos，试求BA，并对其几何意义给予解释。11、已知01-412021AB,，求42232,,,BABABA。12、证明下列等式成立，并从几何变换的角度给予解释：1-0010001200100012参考答案：1、C2、B3、A4、D5、B6、0310A或0113A（答案不唯一）。7、1-104-8、<9、（1）6441；6281；（2）0001；004-2；534-2；0302。10、)cos()sin()sin()cos(BA，表示先将图形绕原点逆时针旋转角，再绕原点逆时针旋转角，实际上相当于将原图形绕原点逆时针旋转角。11、04-45-；80141；6-1-2-3-；4-328-7。12、略，提示：00badcba0001。3