互换性与测量技术基础第四版答案VIP免费

欢迎共阅《互换性与测量技术基础》习题参考解答（第3版）第二章光滑圆柱体结合的公差与配合1.孔或轴最大极限尺寸最小极限尺寸上偏差下偏差公差尺寸标注孔:Φ109.9859.970-0.015-0.0300.015Φ10015.0030.0孔:Φ1818.01718+0.01700.017Φ18017.00孔:Φ3030.01229.991+0.012-0.0090.021Φ30012.0009.0轴:Φ4039.9539.888-0.050-0.1120.062Φ40050.0112.0轴:Φ6060.04160.011+0.041+0.0110.030Φ60041.0011.0轴:Φ858584.9780-0.0220.022Φ850022.02.1)Xmax=0.033-(-0.098)=0.131mmXmin=0-(-0.065)=0.065mmTf=|0.131-0.065|=0.066mm2)Ymax=0–0.060=-0.060mmYmin=0.030–0.041=-0.011mmTf=|-0.060+0.011|=0.049mm3)Xmax=0.007-(-0.016)=0.023mmYmax=-0.018–0=-0.018mmTf=|0.023–(-0.018)|=0.041mm4)Xmax=0.039-0.002=0.037mmYmax=0–0.027=-0.027mmTf=|0.037–(-0.027)|=0.064mm5)Xmax=0.074–(-0.140)=0.214mmXmin=0-(-0.030)=+0.030mmTf=|0.214–0.030|=0.184mm6)Xmax=0.009–(-0.019)=0.028mmYmax=-0.021–0=-0.021mmTf=|0.028–(-0.021)|=0.049mm3.(1)Φ50)(7f)(8H025.0050.0039.00Xmax=0.089mmXmin=0.025mm基孔制、间隙配合（2）Φ80)(10h)(10G0120.0130.0010.0Xmax=0.250mmXmin=0.010mm基轴制、间隙配合（3）Φ30)(6h)(7K0013.0006.0015.0Xmax=0.019mmYmax=-0.015mm基轴制、过渡配合第2题欢迎共阅（4）Φ140)(8r)(8H126.0063.0063.00Ymax=-0.126mmYmin=0mm基孔制、过盈配合（5）Φ180)(6u)(7H235.0210.0040.00Xmax=-0.235mmYmin=-0.170mm基孔制、过盈配合（6）Φ18)(5h)(6M0008.0004.0015.0Xmax=0.004mmYmax=-0.015mm基轴制、过渡配合（7）Φ50)(6js)(7H008.0008.0025.00Xmax=0.033mmYmax=-0.008mm基孔制、过渡配合（8）Φ100)(6k)(7H025.0003.0035.00Xmax=0.032mmYmax=-0.025mm基孔制、过渡配合（9）Φ30)(6n)(7H028.0015.0021.00Xmax=0.006mmYmax=-0.028mm基孔制、过渡配合（10）Φ50)(6h)(7K0016.0007.0018.0Xmax=0.023mmYmax=-0.018mm基轴制、过渡配合4.(1)Φ60)(9h)(9D0074.0174.0100.0(2)Φ30)(8h)(8F0033.0053.0020.0(3)Φ50)(6k)(7H018.0002.0025.00(4)Φ30)(6s)(7H048.0035.0021.00(5)Φ50)(6h)(7U0016.0061.0086.05. Xmin=0.025mm,Xmax=0.066mm.∴配合公差Tf=|0.066–0.025|=0.041mm， Tf=Th+Ts,选基孔制.查表，孔为7级，轴为6级Th=0.025mmTs=0.016mm符合要求.∴选Φ40)(6f)(7H025.0041.0025.00。验算：Xmax=0.025–(-0.041)=0.066mm;Xmin=0–(-0.025)=0.025mm.符合题意。6.1） Tf=|Xmax-Xmin|=|0.086-0.020|=0.066mm,Tf=Th+Ts∴查表选Th=Ts=0.033mm.8级公差。基孔制H8,根据Xmin查表选轴为f8，∴选Φ25)(8f)(8H020.0053.0033.00。验算Xmax、Xmin后符合要求。（2） Tf=|Ymax-Ymin|=|0.076-(-0.035)|=0.041mm,Tf=Th+Ts∴查表选Th为7级，Ts为6级，基孔制H7，根据Ymin查表选轴为u6，∴选Φ41)(6u)(7H076.0060.0025.00验算Ymax、Ymin后符合要求。欢迎共阅(3) Tf=|Xmax-Ymax|=|0.046-(-0.032)|=0.078mm,Tf=Th+Ts∴查表选Ts为7级，Th为8级，基轴制h7，根据Xmax和Ymax查表选孔为K8，∴选Φ60)(7h)(8K0030.0014.0032.0。验算Xmax、Ymax后符合要求。7.Δl=250(a黄铜+a玻璃)Δt=250×(19.5×10-6+8×10-6)×(20+50)=0.048mm,查表Φ50)(7f)(8H025.0050.0039.00,0.039-(-0.050)+0.048=0.137mm，0-(-0.025)+0.048=0.073mm 0.137＞0.075mm,∴原设计Φ50H8/f7配合不合适。重选为：0.075-0.048=0.027mm,0.009-0.048=-0.039mm,装配时的间隙量应为-0.039～0.027mm之间,∴选Φ50)(6n)(8H033.0017.0039.00验算后满足要求。8.Δl=295×[22×(150-20)+12×(100-20)]×10-6=0.181mm;0.04+0.181=0.221mm,0.097+0.181=0.278mm∴装配间隙应为0.221～0.278mm,Tf=|Xmax-Xmax|=|0.278-0.221|=0.057mm,Tf=Th+Ts∴查表选孔为7级，轴为6级，基孔制H7，根据Xmin查表选轴（活塞）为b6,选Φ95)(6b)(7H220.0242.0035.00。验算后基本满足要求。第三章测量技术基础1.29.875－1.005－1.37－7.5=20用4块量块组合；48.98－1.48－7.5=40用3块量块组合；40.79－1.29－9.5=30用3块量块组合；10.56－1.06=9.5...