3.1.2两角和与差的正弦、余弦、正切公式(第一课时)复习1、两角差的余弦公式:)cos(coscossinsinsin()?sin()?cos()?coscos()sinsin()cos[()]coscossinsincos用余弦差角公式推导探求新知coscoscossinsinC(+)()cos2sin2sincos2cossincoscossinsin()用余弦差角及诱导公式推导探求新知2cossin)sincoscossin(S()()上述公式用代,则sin)(sin[()]sincos()cossin()sincoscossinsin)sincoscossin(S()()coscoscossinsincoscossinsin)cos(sinsincoscossinsincoscossinsin()小结1、公式2、公式的应用:正用,逆用。33sin,sin(),54cos()4a例:已知是第四象限的角,求的值。,3解:由sin=-是第四象限的角,得522354cos1sin1(),5sincoscossin442423()2525)4cos(2423()2525举例)4sin(72;10coscossinsin4472;10于是有思考:对于任意角,等式都成立吗?sin(-)=cos()44例4.利用和(差)角公式计算下列各式的值:cos4cossin4;(2)cos20cos70sin20sin70;。。。。。。。。(1)sin722722cos4cossin4。。。。sin722722解:(1)由公式S,得0sin301200sin7242.(2)由公式C,得0cos90000cos2070cos70sinsin70。。。。cos2020举例32cos523已知,,,求sin的值342cos525解:,,,sin3sin43310练习1sincoscossin33(1)0(1)sin75000sin75sin(4530)解:0000sin45cos30cos45sin3023212222624(1)sin34sin26cos34cos26练习2.利用和(差)角公式计算下列各式的值:(2)sin20cos110cos160sin70(1)sin34sin26cos34cos26解:cos34cos26sin34sin26cos3426cos6012(2)sin20cos110cos160sin70(2)sin20cos110cos160sin70解:00sin20cos18070cos18020sin70sin20cos70cos20sin70sin20cos70cos20sin70sin2070sin901练习2.利用和(差)角公式计算下列各式的值:(1)sin34sin26cos34cos2613sincos22xx(1)13sincos22xx(1)解:sincoscossin33xxsin3x举例23sincosxx3sincosxx(2)解:312sincos22xx2sin6x2cossinsincos66xx例5:化简:练习3:化简:22sincosxx13sincos22xx(1)解:sincoscossin33xxsin3x2sincosxx(2)解:2sin2cosxx2sin4x222sincos22xx2sincoscossin44xx22sincossinaxbxabxb探究:,(其中tan=)a131sincos22xx()P137A组T7.T13(1)、(2)、(3)、(4)