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4 .管路的水力计算4.1 绘制管路的系统图1.绘制管路的系统图（1-3）层。并标上管段，管长，以及热负荷大小。2.确定最不利环路，本系统采用异层式系统，取最远的立管为最不利环路。图见附录。4.2 计算最不利环路的管径本设计采用 重力循环系统. (1) 选择最不利环路，并标管径；(2) 根据推荐比摩阻确定环路管径，流速，以及平均比摩阻的大小。(3) 计算各管段的压力损失 Δpy；(4) 确定局部阻力损失 Δpj；(5) 求各管段的压力损失 Δp=Δpy+Δpj；(6) 求环路的总压力损失 ΣΔp；(7) 平衡各管段的阻力；(8) 将计算结果记入下列的表中。水力计算表管段号QWGKg/hLmdmmVm/sRPa/mΔpy=R LξΔpdΔpjΔp123456789101112立管Ⅰ一层散热器（最不利环路 ） 作用压力 Δp =764.41pa11698582200.0452.214.42250.9924.7529.172963833210320.084.9449.4043.8915.5664.9731926466318400.148.81158.585.59.6453.02211.6438528132527700.102.5268.0464.9229.5297.565192646635400.148.8144.053.59.6433.7477.796963833219320.0894.9493.8643.8915.56109.42760002063.3250.18.2427.1944.9219.6846.87832521123.3250.0522.759.0841.335.3215.12ΣL=87.6m Σ（Δpy+Δpj）=652.49pa系统作用压力富裕率 X=(764.41-652.49)/764.41=14.64%>10%入口处的剩余循环作用压力，用阀门截流。立管Ⅰ二层散热器 作用压力 Δp =1278.88pa963862203.3150.32144.52476.92550.38251.90728.82101435492150.078.9217.84312.1474.7392.57Σ（Δpy+Δpj）=821.39pa不平衡率 X=(546.81-821.39)/546.81=-35%>-15%(管径最小应调节立管阀门) 立管Ⅰ三层散热器 作用压力 Δp =1793.22pa1136381253.3150.1849.57163.58515.9479.70243.28121914662150.09615.330.6314.53140.56171.16Σ（Δpy+Δpj）(9-12)=1143.26pa不平衡率 X=(1119.97-1143.26)/546.81=-2.07%<15%立管Ⅱ一层散热器环路 资用压力 Δp =265.54pa1396293310.5320.0940922.4633.9911.9614.42141042362150.0553.266.52271.4940.1946.711532281113.3200.188.8129.07415.9463.7691.831661272113.3250.118.6228.4545.9523.8152.261796263313.3320.094.9216.2433.9911.9628.2不平衡率 X=(265.54-234.42)/265.54=-11.7%<-15%立管Ⅱ二层散热器资用压力 作用压力 Δp =1278.88pa1864162213.3150.33145478.5553.58267.8746619909312150.042.735.46310.792.367.82Σ（Δpy+Δpj）=754.2pa不平衡率 X=(65...