平方差完全平方练习题1.计算: (1)))((xyxyx2(2)1)12)(12(xx(3)))(()(xxxx221(4)x(x+2)+(2x+1)(2x-1)(5) abababba323222(6)22)2()12(xx(7) a(a-2b) -(a-b) 2 (8) (2a+1)2-(1-2a) 2(9) (x-2y)(x+2y)-(x+2y)2(10))2)((4)2(2yxyxyx(11) (3x-y)2-(2x+y)2+5x(y-x) (12) zyxzyx(13) (-7+ a+b)(-7-a-b) ※(14))12)(12(yxyx※(15)5353baba(16).化简求值22)2()2()2)(12(xxxx,其中211x2.化简求值:(1)(x+2y)(x-2y)-(2x- y)(-2x-y),x=8, y=- 8(2)(21x+31y)(31y-21x)+21x·(21x-31y),其中 x= 4,y=63.利用平方差公式计算:(1) 31×29 (2)108×112 (3)× (4)20 23× 1913(5) 20102-2011×2009 (6) 110199100※4.若 x-y=3,x·y=10,求 x2+y2 的值.※5.已知 x+y=1,求 12x2+xy+12y 2 的值.6.已知2)()1(2yxxx,求xyyx222的值.※7.若 x+1x=3,求 (x+1x)2; x2+ 1x2;(x- 1x)一、配方:(1)22_______23 xx(2)22_______324xx(3)222____9___4yx(4)22216xa需要先变形再用平方差公式1、(-2x-y)(2x-y) 2、(y-x)(-x-y) 3
(-2x+y)(2x+y) 4
(4a-1)(-4a-1)5
(b+2a)(2a-b) 6
(a+b)(-b+a)7