第八章数值积分/*NumericalIntegration*/近似计算badxxfI)(§8
1Newton-Cotes公式思路利用插值多项式则积分易算
)()(xfxPn要求:积分易算
1梯形公式用直线代替y=f(x):f(x)abf(b)()()()()[()()]22baIfxdxfafbbabafafbf(a)101100110()()()()()()()()fxfxfxpxRxfxxxRxxx用一次插值代替f(x):10101100100010210000102100001010100101010()()()[()()]()()[()()()]|2()()()()()|()|2()[()()]()()()2[()()]()bxaxxxxxxxfxfxIfxdxfxxxdxxxfxfxfxxxxxxxfxfxfxxxxxxxfxfxxxfxxxfxfxxx[()()]22bafafb梯形公式
误差:101100(1)110(2)(2)1010(2)(2)0101(2)33(2)10()()()()(1)
()()()()()2
()()()()()()22()1[()]()2612nnbbxiaaibxxxiaxixxxxxfRfRxdxxxdxnffxxdxxxxxdxffxxxxdxxxxxdxfhxxf113(2)1000103(2)()()()()()()()()12[()()]()212bbbaaaIfxdxpxdxRxdxfxfxhfxxxfxxhhfafbf利用积分中值定律(2)(2)(2)()0()0()0fff时偏大