综合练习1.x3m+1可写成[]A.(x)3m+1B.(xm)3+1C.x·x3mD.(xm)2m+12.a2(a2b2)2的结果是[]A.a4b4B.a6b4C.a8b4D.a6b23.下面等式中,错误的是[]A.(ab2)2=a2b4B.(m3n2)5=m15n10C.(2x2)2=4x4D.(4xmy3)3=64x3my9A.a6B.a5C.a8D.a95.(y3)4+(y4)3等于A.2y12B.y24C.2y24D.y144计算:(1)(-5ab)3(2)-(3x2y)2(3)(-1ab2c3)3(4)(-xmy3m)2.(5)(-a2)2·(-2a3)2(6)[(x+y)2]3·[(x+y)3]4;解答题1)2,3nnxy,求()nxy,23()nxy的值。2)已知x2n=3,求(3x3n)2的值.3)若162,273yx,求:yx的值。4)已知105,106ab,求(1)231010ab的值;(2)2310ab的值