sql存储过程的加密和解密方法(含sql2000和sql2005版本VIP免费

sql 存储过程的加密和解密(有 sql2000 和 sql2005) ★加密存储过程： IF EXISTS (SELECT name FROM sy sobjects WHERE name = 'encry pt_this' AND ty pe = 'P') DROP PROCEDURE encry pt_this GO USE pu bs GO CREATE PROCEDURE encrypt_this WITH ENCRYPTION ---只需要在创建时加入WITH ENCRYPTION 即可 AS SELECT * FROM authors GO --查看存储过程文本： EXEC sp_helptext encrypt_this 下面是结果集： The object's comments have been encrypted. ----对象已经被加密 ★解密存储过程： CREATE PROCEDURE sp_decrypt(@objectName varchar(50)) AS begin set nocount on --CSDN： j9988 copyright:2004.04.15 --V3.1 --破解字节不受限制，适用于SQLSERVER2000 存储过程，函数，视图，触发器 --修正上一版视图触发器不能正确解密错误 --发现有错，请E_MAIL： CSDNj9988@tom.com begin tran declare @objectname1 varchar(100),@orgvarbin varbinary(8000) declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000) DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000) declare @i int,@status int,@type varchar(10),@parentid int declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@ObjectName) create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int) insert #temp SELECT number,colid,ctext,encrypted,status FROM syscomments WHERE id = object_id(@objectName) select @number=max(number) from #temp set @k=0 while @k<=@number begin if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k) begin if @type='P' set @sql1=(case when @number>1 then 'ALTER PROCEDURE '+ @objectName +';'+rtrim(@k)+' WITH ENCRYPTION AS ' else 'ALTER PROCEDURE '+ @objectName+' WITH ENCRYPTION AS ' end) if @type='TR' begin declare @parent_obj...