第十六章分式第十六章分式一、提出问题:请问下面的运算过程对吗
32)3(4422xxxxx32)3()2(22xxxx22x正确的解法:32)3(4422xxxxx2)3)(2(2xx除法转化为乘法之后可以运用乘法的交换律和结合律2)2x(23x13x2x23223)()2(abbaaba(2)221232)()2()()2(yxyxyxyx(3)例1
(1)4232)()(abcabccba)(4232)()(abcabccba)(练习:计算:1
4.aaaaaaaaa2444122222)225(423xxxxxxxxxxxx424422230243])()()()([babababa例2
111111aa:,01a3a:2求已知例aa1)1(221)2(aa2)1)(3(aa441)4(aa的值
求已知221,31)1
(1xxxx的值
求已知1,51)2(242aaaaa的值
求分式满足已知acbcababc,51acca,41cbbc,31baabc,b,a
2综合练习的值
求,已知mmxxxx0141
3222的值
求分式已知yxyxyxyxyx252373,211
4综合练习53xa_________aaaaxx2x2x6、先化简再求值22222222yxyxyxyx其中x=-2,y=-3720052004200810031(1)()(2);21(2)()9332)1()1(xx81、当x为何值时,有意义