代数学:具体——抽象•从从从从从从从从•从从-从从从从从从从从从从从•从从从从从从•从从从从从从从•从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从•从从从从从从从从从从从从从从从从从从从从从1从从从从从从从从从从从从“从从从从从从从从从从从从从从从从从从从从从”.122121222,0111122222bbbbbbbxxbxxxx泥板给出如下解法:或解这个问题相当于解:“从从从从从从从从从从从从从从从从从从从”.222222,022222abbababbbabxxbyxayx泥板给出如下解法:或解这个问题相当于解:“从从从从从从从从从从从1000从从从从从从从从从从从从从从从从从从从从从从从从从从从10从从从从从从从从从从从从从从”.101032303010100010100010,,,103210002222222表示长、宽表示面积,yxyxxyyx2从从从从从从从从从x³+x²=10xx²x³x³+x²1112从从从从从从从2481210从[2,12]从从8/10从392736从x=1从84166480从从从从从从从从3从从从从从从“从从从从20%从从从从从从从从从从从从从从从从从”(1+20%)n=2从从从从从从3n4从从从从从从从(1+20%)4-24-n=—————————从(1+20%)4-(1+20%)³从从从从从从从从从从从Rhind从从从从31从从“从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从33从”从从从从从从从从从从从从从从从从从从Rhind从从从从63从从“从700从从从从从4从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从”33712132xxxx.1412170014121141211412114131213270041312132,即得的,再求,得除再用,相加,得,,,古埃及人解法:先把xxxxRhind从从从从40从从“5从从从100从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从”。其和,,,,,计算得:。,,,,分别乘以用,于是)所以(,由于。能够得到以;然后计算什么数乘,其和为,,,,分别为个人所得面包数,则假设差为故埃及人的解法:首先100313861292061321032123211712216132110060321406032,6060110060602321171221615215从从从从从从从从从从从从从从从从从2从“从从从从从”从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从2从从从1~10,从从从从从从从从从从从a(b+c+d+从)=ab+ac+ad+从(a+b)a+(a+b)b=(a+b²)(a+b)a=a²+ab(a+b)²=a²+b²+2abab+[(a+b)/2-b]²=[(a+b)/2]²(a+b)b+(a/2)²=(a/2+b)²(a+b)²+a²=2(a+b)a+b²4(a+b)a+b²=(2a+b)²(a+b)²+b²=2[(a/2)²+(a/2+b)²](a-b)²+b²=2[(a/2)²+(a/2-b)²]从从从从从2从从从11从“从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从”从AB=a从AH=x从从从a(a-x)=x²x²+ax-a²=0从从从从ABCD从AE=ED从从EA从从EF=EB从从从从AFGHAH从从从从.215,01,12xxxa则若从从从从从从从从从从从从从从从从从xx²x³x4x5x6从从从从从从__从____3x²+12从M“”从从“=”__从_x²+2x+3从M____从_x6-5x4+x²-3x-2从M从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从•从从从-从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从•从从从-从从从从从从从从从从从从从从从从从从从从从1从从从-从从从从(Al-Khowarizmi从MohammedibnMusa从从780~840从从从850)从从从Al-jabrW`almuqabala从从从从从从从“从从从从从”从从从从从从从Algebra从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从从“从”从“从”从“从从”从从从从从x从x²从从从从从从6从从从从ax²=bxax²=cbx=cax²=bx+cax²+bx=cax²+c=b...