1.计算:(1)(2)(3)211;x22;mnnmnmn.2213+1aaaa2212(1)31===11111;xxxxxxxx解:(1)2=222()2()21===2()2()2;mnnmnnmnmnmnmnmnnmnmnmn(2).222131(3)+=+1(1)(1)(1)(1)1+(3)(1)(1)===(1)(1)(1)(1)(1)aaaaaaaaaaaaaaaaaaaaaaaaaa(3)1.计算:(1)(2)(3)211;x22;mnnmnmn.2213+1aaaa2.先化简,再求值:解:2+1+1+1+1=+11+1111+1+2=+=111;aaaaaaaaaaaaaa(1)2+1+111aaaa(1)当1=10a时,求的值;224+xyxyxyxy(2)设x=3y,求的值.因为1=10a,所以,原式=1+2710=13110;2.先化简,再求值:(2)解:()()()()()()()()22224+4+=++==.++xyxyxyxyxyxyxyxyxyxyxyxyxyxyxy2+1+111aaaa(1)当1=10a时,求的值;224+xyxyxyxy(2)设x=3y,求的值.因为x=3y,所以,原式=321==.3+42yyyyyy